-12x^2-13x+35=0

Solution for -12x^2-13x+35=0 equation:

-12x^2-13x+35=0

a = -12; b = -13; c = +35;
Δ = b2-4ac
Δ = -132-4·(-12)·35
Δ = 1849
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1849}=43$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-43}{2*-12}=\frac{-30}{-24}
=1+1/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+43}{2*-12}=\frac{56}{-24}
=-2+1/3
$